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1082 射击比赛

本题目给出的射击比赛的规则非常简单,谁打的弹洞距离靶心最近,谁就是冠军;谁差得最远,谁就是菜鸟。本题给出一系列弹洞的平面坐标(x,y),请你编写程序找出冠军和菜鸟。我们假设靶心在原点(0,0)。

输入格式:

输入在第一行中给出一个正整数 N(≤ 10 000)。随后 N 行,每行按下列格式给出:

ID x y
ID x y

其中 ID 是运动员的编号(由 4 位数字组成);xy 是其打出的弹洞的平面坐标(x,y),均为整数,且 0 ≤ |x|, |y| ≤ 100。题目保证每个运动员的编号不重复,且每人只打 1 枪。

输出格式:

输出冠军和菜鸟的编号,中间空 1 格。题目保证他们是唯一的。

输入样例:

tex
3
0001 5 7
1020 -1 3
0233 0 -1
3
0001 5 7
1020 -1 3
0233 0 -1

输出样例:

tex
0233 0001
0233 0001

Solution:

java
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.StreamTokenizer;
import java.util.ArrayList;
import java.util.Arrays;

public class Main {
    public static void main(String[] args) throws IOException {
        StreamTokenizer in = new StreamTokenizer(new BufferedReader(new InputStreamReader(System.in)));
        in.nextToken();
        int n = (int) in.nval;
        int[] id = new int[n];
        double[] score = new double[n];
        for (int i = 0; i < n; i++) {
            in.nextToken();
            id[i] = (int) in.nval;
            in.nextToken();
            int x = (int) in.nval;
            in.nextToken();
            int y = (int) in.nval;
            double res = Math.sqrt(Math.pow(Math.abs(x), 2) + Math.pow(Math.abs(y), 2));
            score[i] = res;
        }
        ArrayList<Double> a = new ArrayList<Double>();
        for (double v : score) {
            a.add(v);
        }
        Arrays.sort(score);
        System.out.printf("%04d %04d", id[a.indexOf(score[0])], id[a.indexOf(score[n - 1])]);
    }
}
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.StreamTokenizer;
import java.util.ArrayList;
import java.util.Arrays;

public class Main {
    public static void main(String[] args) throws IOException {
        StreamTokenizer in = new StreamTokenizer(new BufferedReader(new InputStreamReader(System.in)));
        in.nextToken();
        int n = (int) in.nval;
        int[] id = new int[n];
        double[] score = new double[n];
        for (int i = 0; i < n; i++) {
            in.nextToken();
            id[i] = (int) in.nval;
            in.nextToken();
            int x = (int) in.nval;
            in.nextToken();
            int y = (int) in.nval;
            double res = Math.sqrt(Math.pow(Math.abs(x), 2) + Math.pow(Math.abs(y), 2));
            score[i] = res;
        }
        ArrayList<Double> a = new ArrayList<Double>();
        for (double v : score) {
            a.add(v);
        }
        Arrays.sort(score);
        System.out.printf("%04d %04d", id[a.indexOf(score[0])], id[a.indexOf(score[n - 1])]);
    }
}

Released under the MIT License.