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1069 微博转发抽奖

小明 PAT 考了满分,高兴之余决定发起微博转发抽奖活动,从转发的网友中按顺序每隔 N 个人就发出一个红包。请你编写程序帮助他确定中奖名单。

输入格式:

输入第一行给出三个正整数 M(≤ 1000)、N 和 S,分别是转发的总量、小明决定的中奖间隔、以及第一位中奖者的序号(编号从 1 开始)。随后 M 行,顺序给出转发微博的网友的昵称(不超过 20 个字符、不包含空格回车的非空字符串)。

注意:可能有人转发多次,但不能中奖多次。所以如果处于当前中奖位置的网友已经中过奖,则跳过他顺次取下一位。

输出格式:

按照输入的顺序输出中奖名单,每个昵称占一行。如果没有人中奖,则输出 Keep going...

输入样例 1:

tex
9 3 2
Imgonnawin!
PickMe
PickMe
LookHere
Imgonnawin!
TryAgainAgain
TryAgainAgain
Imgonnawin!
TryAgainAgain
9 3 2
Imgonnawin!
PickMe
PickMe
LookHere
Imgonnawin!
TryAgainAgain
TryAgainAgain
Imgonnawin!
TryAgainAgain

输出样例 1:

tex
PickMe
Imgonnawin!
TryAgainAgain
PickMe
Imgonnawin!
TryAgainAgain

输入样例 2:

tex
2 3 5
Imgonnawin!
PickMe
2 3 5
Imgonnawin!
PickMe

输出样例 2:

tex
Keep going...
Keep going...

Solution:

java
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.HashSet;
import java.util.Set;

public class Main {

	public static void main(String[] args) throws IOException {
		BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
		String[] arr = in.readLine().split(" ");
		int M = Integer.parseInt(arr[0]);
		int N = Integer.parseInt(arr[1]);
		int S = Integer.parseInt(arr[2]);
		String[] names = new String[M];
		for (int i = 0; i < M; i++) {
			names[i] = in.readLine();
		}
		in.close();
		Set<String> set = new HashSet<String>();
		StringBuffer sb = new StringBuffer();
		// 顺延后还是按照原先间隔中奖
		int j;
		for (int i = S - 1; i < M; i += N + (j - i)) {
			for (j = i; j < M; j++) {
				if (!set.contains(names[j])) {
					set.add(names[j]);
					sb.append(names[j]).append("\n");
					break;
				}
			}
		}
		System.out.print(set.size() == 0 ? "Keep going..." : sb);
	}

}
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.HashSet;
import java.util.Set;

public class Main {

	public static void main(String[] args) throws IOException {
		BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
		String[] arr = in.readLine().split(" ");
		int M = Integer.parseInt(arr[0]);
		int N = Integer.parseInt(arr[1]);
		int S = Integer.parseInt(arr[2]);
		String[] names = new String[M];
		for (int i = 0; i < M; i++) {
			names[i] = in.readLine();
		}
		in.close();
		Set<String> set = new HashSet<String>();
		StringBuffer sb = new StringBuffer();
		// 顺延后还是按照原先间隔中奖
		int j;
		for (int i = S - 1; i < M; i += N + (j - i)) {
			for (j = i; j < M; j++) {
				if (!set.contains(names[j])) {
					set.add(names[j]);
					sb.append(names[j]).append("\n");
					break;
				}
			}
		}
		System.out.print(set.size() == 0 ? "Keep going..." : sb);
	}

}

Released under the MIT License.