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1011 A+B 和 C

给定区间 [−231,231] 内的 3 个整数 ABC,请判断 A+B 是否大于 C

输入格式:

输入第 1 行给出正整数 T (≤10),是测试用例的个数。随后给出 T 组测试用例,每组占一行,顺序给出 ABC。整数间以空格分隔。

输出格式:

对每组测试用例,在一行中输出 Case #X: true 如果 A+B>C,否则输出 Case #X: false,其中 X 是测试用例的编号(从 1 开始)。

输入样例:

tex
4
1 2 3
2 3 4
2147483647 0 2147483646
0 -2147483648 -2147483647
4
1 2 3
2 3 4
2147483647 0 2147483646
0 -2147483648 -2147483647

输出样例:

tex
Case #1: false
Case #2: true
Case #3: true
Case #4: false
Case #1: false
Case #2: true
Case #3: true
Case #4: false

Solution:

java
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class Main {
    public static void main(String[] args) throws IOException {
        BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
        int n = Integer.parseInt(in.readLine());
        StringBuilder sb = new StringBuilder();
        for (int i = 1; i <= n; i++) {
            String[] input = in.readLine().split(" ");
            long a = Long.parseLong(input[0]);
            long b = Long.parseLong(input[1]);
            long c = Long.parseLong(input[2]);
            sb.append(String.format("Case #%d: ", i)).append(a + b > c ? "true" : "false");
            if (i < n) sb.append("\n");
        }
        System.out.println(sb);
    }
}
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class Main {
    public static void main(String[] args) throws IOException {
        BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
        int n = Integer.parseInt(in.readLine());
        StringBuilder sb = new StringBuilder();
        for (int i = 1; i <= n; i++) {
            String[] input = in.readLine().split(" ");
            long a = Long.parseLong(input[0]);
            long b = Long.parseLong(input[1]);
            long c = Long.parseLong(input[2]);
            sb.append(String.format("Case #%d: ", i)).append(a + b > c ? "true" : "false");
            if (i < n) sb.append("\n");
        }
        System.out.println(sb);
    }
}

Released under the MIT License.