1002 写出这个数
读入一个正整数 n，计算其各位数字之和，用汉语拼音写出和的每一位数字。
输入格式：
每个测试输入包含 1 个测试用例，即给出自然数 n 的值。这里保证 n 小于 10100。
输出格式：
在一行内输出 n 的各位数字之和的每一位，拼音数字间有 1 空格，但一行中最后一个拼音数字后没有空格。
输入样例：
tex
12345678909876543211234567891234567890987654321123456789输出样例：
tex
yi san wuyi san wuSolution：
java
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
public class Main {
public static void main(String[] args) throws IOException {
BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
char[] chars = in.readLine().toCharArray();
int sum = 0;
for (char aChar : chars) {
sum += aChar - '0';
}
StringBuilder sb = new StringBuilder();
String[] arr = {"ling", "yi", "er", "san", "si", "wu", "liu", "qi", "ba", "jiu"};
while (sum != 0) {
sb.insert(0, arr[sum % 10] + " ");
sum /= 10;
}
System.out.println(sb.toString().trim());
}
}import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
public class Main {
public static void main(String[] args) throws IOException {
BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
char[] chars = in.readLine().toCharArray();
int sum = 0;
for (char aChar : chars) {
sum += aChar - '0';
}
StringBuilder sb = new StringBuilder();
String[] arr = {"ling", "yi", "er", "san", "si", "wu", "liu", "qi", "ba", "jiu"};
while (sum != 0) {
sb.insert(0, arr[sum % 10] + " ");
sum /= 10;
}
System.out.println(sb.toString().trim());
}
}